What are the different types of JC Chemistry tuition classes available at your centre?

We have 3 modes of learning for students to choose from: weekly physical classes at Bishan; weekly online lessons via Zoom; and on-demand video lessons.

Are you the only Chemistry tutor conducting the classes or do you engage other tutors to do that?

Please be rest assured that I conduct all my classes personally and I do not engage other tutors to teach at my centre.

How well do your students perform after attending your H2 Chemistry tuition classes?

Most of my students showed improvements by at least 3 grades and more than 80% have attained distinction for A Levels. The earlier the students join my classes, the more confident I am in improving their grades.

What is your class size at Bishan?

Usually the class size is around 10 to 12 students. Max class size is 16 pax.

Is there makeup lesson if I miss a class?

Yes makeup lesson is available in the same week subject to availability. If makeup class is not possible, the student can view the recorded video lessons at Google Classroom.

Do you have trial lesson available? How much is it?

Yes we do. Fees for trial lesson are for Bishan class and for Zoom online class.

Does your centre offer O Level chemistry tuition? Do you teach IB / IP chemistry tuition? How about H1 Chemistry?

Chemistry Guru specialises in H2 Chemistry for JC1 and JC2 or IP Year 5 and IP Year 6 students only. Find out all the information about A Level H2 Chemistry and the detailed comparison between H1 and H2 Chemistry. We do not conduct lessons for H1 Chemistry, O Level Chemistry, IB Chemistry or IP Chemistry at IP Year 3 and IP Year 4.

2022 A Level H2 Chemistry Paper 1 Solutions - Questions 1 to 10

Question 1

2022 p1 1 question

Answer: C

Topic: Chemical Bonding

Explanation:

NaF is ionic compound with strongest ionic bond between oppositely charged ions, hence highest boiling point.

CH₃CH₂CH₃ is non-polar molecule with weak id-id attraction between molecules hence lowest boiling point.

CH₃CH₂NH₂ and CH₃CH₂OH can form hydrogen bonds between molecules so boiling points are higher than CH₃CH₂CH₃.

Comparing CH₃CH₂NH₂ and CH₃CH₂OH, CH₃CH₂OH can form stronger H-bonds between molecules since O-H bond is more polar than N-H bond.

Therefore boiling point of CH₃CH₂NH₂ will be lower than CH₃CH₂OH.

2022 p1 1 explain

Question 2

2022 p1 2 question

Answer: C

Topic: Atomic Structure

Explanation:

Br has more inner shells, greater shielding effect, lower effective nuclear charge, weaker attraction between nucleus and valence electrons hence less electronegative than Cl.

Therefore in Br-Cl bond, less electronegative Br will be partial positive charge while more electronegative Cl will be partial negative.

2022 p1 2 explain

Question 3

2022 p1 3 question

Answer: D

Topic: Ionic Equilibria

Explanation:

Thioacetic acid has lower pK_a value hence more acidic than ethanoic acid.

Hence H⁺ should be more easily removed from thioacetic acid instead of ethanoic acid, K_a value for thioacetic acid is larger, and thioacetic acid should have a lower pH in both acids of same concentration.

2022 p1 3 explain

Question 4

2022 p1 4 question

Answer: C

Topic: Gaseous State

Explanation:

Use Ideal Gas Equation PV = nRT to calculate moles of entonox, moles of N₂O and finally mass of N₂O.

2022 p1 4 explain

Question 5

2022 p1 5 question

Answer: A

Topic: Periodicity

Explanation:

AlCl₃ will dissolve in water to form Al³⁺(aq) which can hydrolyse water to release H⁺ due to its high polarising power.

The solution, pH = 3, is acidic enough to react with Na₂CO₃ to form CO₂ gas.

MgCl₂ will dissolve in water to form Mg²⁺(aq) which can also hydrolyse water, but solution is less acidic, pH = 6 and not acidic enough to react with carbonate.

NaCl only dissolves in water and does not hydrolyse water, pH = 7.

2022 p1 5 explain

Question 6

2022 p1 6 question

Answer: B

Topic: Periodicity

Explanation:

Fluorine is the most electronegative element and eletronegativity decreases as we move away from F.

X is more electronegative than As and adjacent elements in same group, hence X is Phosphorus.

Y is more electronegative than X and adjacent elements in same period, hence Y is Sulfur.

2022 p1 6 explain

Question 7

2022 p1 7 question

Answer: A

Topic: Mole Concept

Explanation:

Calculate mass of B₂O₃ in 100g, moles of B₂O₃ and moles of B.

Calculate mass of PbO in 100g, moles of PbO and moles of Pb.

Then compare mole ratio of Pb to B.

2022 p1 7 explain

Question 8

2022 p1 8 question

Answer: B

Topic: Periodicity

Explanation:

The 4 elements mentioned in Group 15, 16 and Period 3, 4 are P, S, As and Se.

We write out the electronic configuration of M⁵⁺ for each element to deduce which subshell the 6th electron is residing.

For P, 6th electron removed from 2nd principal quantum shell, closest to nucleus, hardest to remove hence highest 6th IE.

For Se, 6th electron removed from 4th shell, furthest from the nucleus hence easiest to remove, lowest 6th IE.

Finally comparing S & As, 6th electron removed from the same 3rd shell, As will have greater ENC and 6th IE for As will be greater than S.

6th IE trend will therefore be Se < S < As < P and we can identify sulfur to be element H.

2022 p1 8 explain

Question 9

2022 p1 9 question

Answer: B

Topic: Atomic Structure

Explanation:

The process is removing electron from I^-, Xe and Cs⁺.

All species have same number of electrons hence same shielding effect with increaing nuclear charge due to increasing proton number. ENC and IE decrease in the order Cs⁺ > Xe > I^-

2022 p1 9 explain