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We have 3 modes of learning for students to choose from: weekly physical classes at Bishan; weekly online lessons via Zoom; and on-demand video lessons.

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Please be rest assured that I conduct all my classes personally and I do not engage other tutors to teach at my centre.

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Most of my students showed improvements by at least 3 grades and more than 80% have attained distinction for A Levels. The earlier the students join my classes, the more confident I am in improving their grades.

What is your class size at Bishan?

Usually the class size is around 10 to 12 students. Max class size is 16 pax.

Is there makeup lesson if I miss a class?

Yes makeup lesson is available in the same week subject to availability. If makeup class is not possible, the student can view the recorded video lessons at Google Classroom.

Do you have trial lesson available? How much is it?

Yes we do. Fees for trial lesson are for Bishan class and for Zoom online class.

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Chemistry Guru specialises in H2 Chemistry for JC1 and JC2 or IP Year 5 and IP Year 6 students only. Find out all the information about A Level H2 Chemistry and the detailed comparison between H1 and H2 Chemistry. We do not conduct lessons for H1 Chemistry, O Level Chemistry, IB Chemistry or IP Chemistry at IP Year 3 and IP Year 4.

Determine Limiting Reagent

In this video we want to discuss how to determine the limiting reagent for mole concept questions, and use the limiting reagent to determine the amount of products formed.

Let Chemistry Guru, Singapore's top JC Chemistry tuition centre, guide you through an example:

determine limiting reagent question

It is important for students not to assume that all the Na₂CO₃ will completely react with all the HCl.

We have to determine if one of the reactants is limiting, and therefore the amount of CO₂ formed is based on the limiting reagent.

First let's calculate the amount of both reactants.

determine limiting reagent determine moles of reactants

Next, to determine the limiting reagent, we calculate the amount of reactant B required to completely react with all of reactant A.

In this case if we react 100% of Na₂CO₃ which is 0.05000 mol, how much of HCl is required?

determine limiting reagent determine which reactant is limiting

Based on the calculation, we need 0.1000 mol of HCl to react with 100% of Na₂CO₃, but we only have 0.08000 mol of HCl.

This means that HCl is limiting and Na₂CO₃ is in excess.

Sidenote:

If based on the calculation we have enough HCl to react with 100% of Na₂CO₃, this means after all the Na₂CO₃ is used up, we will still have excess HCl left.

In this case then Na₂CO₃ is limiting and HCl is in excess.

Finally we can use the limiting reagent to determine the amount and volume of CO₂ produced.

determine limiting reagent determine amount of product based on limiting reagent

For the detailed step-by-step discussion on how to determine limiting reagent, check out this video!

Topic: Mole Concept, Physical Chemistry, A Level Chemistry, Singapore

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Determine Limiting Reagent